Optimal. Leaf size=185 \[ -\frac{b^{3/2} (4 b c-5 a d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x^4}}{\sqrt{b c-a d}}\right )}{4 a^3 (b c-a d)^{3/2}}+\frac{(a d+4 b c) \tanh ^{-1}\left (\frac{\sqrt{c+d x^4}}{\sqrt{c}}\right )}{4 a^3 c^{3/2}}-\frac{b \sqrt{c+d x^4} (2 b c-a d)}{4 a^2 c \left (a+b x^4\right ) (b c-a d)}-\frac{\sqrt{c+d x^4}}{4 a c x^4 \left (a+b x^4\right )} \]
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Rubi [A] time = 0.648915, antiderivative size = 185, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292 \[ -\frac{b^{3/2} (4 b c-5 a d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d x^4}}{\sqrt{b c-a d}}\right )}{4 a^3 (b c-a d)^{3/2}}+\frac{(a d+4 b c) \tanh ^{-1}\left (\frac{\sqrt{c+d x^4}}{\sqrt{c}}\right )}{4 a^3 c^{3/2}}-\frac{b \sqrt{c+d x^4} (2 b c-a d)}{4 a^2 c \left (a+b x^4\right ) (b c-a d)}-\frac{\sqrt{c+d x^4}}{4 a c x^4 \left (a+b x^4\right )} \]
Antiderivative was successfully verified.
[In] Int[1/(x^5*(a + b*x^4)^2*Sqrt[c + d*x^4]),x]
[Out]
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Rubi in Sympy [A] time = 75.4899, size = 158, normalized size = 0.85 \[ - \frac{\sqrt{c + d x^{4}}}{4 a c x^{4} \left (a + b x^{4}\right )} - \frac{b \sqrt{c + d x^{4}} \left (a d - 2 b c\right )}{4 a^{2} c \left (a + b x^{4}\right ) \left (a d - b c\right )} + \frac{b^{\frac{3}{2}} \left (5 a d - 4 b c\right ) \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{c + d x^{4}}}{\sqrt{a d - b c}} \right )}}{4 a^{3} \left (a d - b c\right )^{\frac{3}{2}}} + \frac{\left (a d + 4 b c\right ) \operatorname{atanh}{\left (\frac{\sqrt{c + d x^{4}}}{\sqrt{c}} \right )}}{4 a^{3} c^{\frac{3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/x**5/(b*x**4+a)**2/(d*x**4+c)**(1/2),x)
[Out]
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Mathematica [C] time = 1.21083, size = 489, normalized size = 2.64 \[ \frac{\frac{5 b d x^4 \left (-a^2 d \left (3 c+2 d x^4\right )+3 a b \left (c^2+c d x^4-d^2 x^8\right )+2 b^2 c x^4 \left (c+3 d x^4\right )\right ) F_1\left (\frac{3}{2};\frac{1}{2},1;\frac{5}{2};-\frac{c}{d x^4},-\frac{a}{b x^4}\right )+3 \left (c+d x^4\right ) \left (a^2 d+a b \left (d x^4-c\right )-2 b^2 c x^4\right ) \left (2 a d F_1\left (\frac{5}{2};\frac{1}{2},2;\frac{7}{2};-\frac{c}{d x^4},-\frac{a}{b x^4}\right )+b c F_1\left (\frac{5}{2};\frac{3}{2},1;\frac{7}{2};-\frac{c}{d x^4},-\frac{a}{b x^4}\right )\right )}{c (b c-a d) \left (-5 b d x^4 F_1\left (\frac{3}{2};\frac{1}{2},1;\frac{5}{2};-\frac{c}{d x^4},-\frac{a}{b x^4}\right )+2 a d F_1\left (\frac{5}{2};\frac{1}{2},2;\frac{7}{2};-\frac{c}{d x^4},-\frac{a}{b x^4}\right )+b c F_1\left (\frac{5}{2};\frac{3}{2},1;\frac{7}{2};-\frac{c}{d x^4},-\frac{a}{b x^4}\right )\right )}+\frac{6 a b d x^8 (a d-2 b c) F_1\left (1;\frac{1}{2},1;2;-\frac{d x^4}{c},-\frac{b x^4}{a}\right )}{(a d-b c) \left (x^4 \left (2 b c F_1\left (2;\frac{1}{2},2;3;-\frac{d x^4}{c},-\frac{b x^4}{a}\right )+a d F_1\left (2;\frac{3}{2},1;3;-\frac{d x^4}{c},-\frac{b x^4}{a}\right )\right )-4 a c F_1\left (1;\frac{1}{2},1;2;-\frac{d x^4}{c},-\frac{b x^4}{a}\right )\right )}}{12 a^2 x^4 \left (a+b x^4\right ) \sqrt{c+d x^4}} \]
Warning: Unable to verify antiderivative.
[In] Integrate[1/(x^5*(a + b*x^4)^2*Sqrt[c + d*x^4]),x]
[Out]
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Maple [B] time = 0.02, size = 938, normalized size = 5.1 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/x^5/(b*x^4+a)^2/(d*x^4+c)^(1/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (b x^{4} + a\right )}^{2} \sqrt{d x^{4} + c} x^{5}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^4 + a)^2*sqrt(d*x^4 + c)*x^5),x, algorithm="maxima")
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Fricas [A] time = 0.358729, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^4 + a)^2*sqrt(d*x^4 + c)*x^5),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/x**5/(b*x**4+a)**2/(d*x**4+c)**(1/2),x)
[Out]
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GIAC/XCAS [A] time = 0.222698, size = 362, normalized size = 1.96 \[ \frac{1}{4} \, d^{3}{\left (\frac{{\left (4 \, b^{3} c - 5 \, a b^{2} d\right )} \arctan \left (\frac{\sqrt{d x^{4} + c} b}{\sqrt{-b^{2} c + a b d}}\right )}{{\left (a^{3} b c d^{3} - a^{4} d^{4}\right )} \sqrt{-b^{2} c + a b d}} - \frac{2 \,{\left (d x^{4} + c\right )}^{\frac{3}{2}} b^{2} c - 2 \, \sqrt{d x^{4} + c} b^{2} c^{2} -{\left (d x^{4} + c\right )}^{\frac{3}{2}} a b d + 2 \, \sqrt{d x^{4} + c} a b c d - \sqrt{d x^{4} + c} a^{2} d^{2}}{{\left (a^{2} b c^{2} d^{2} - a^{3} c d^{3}\right )}{\left ({\left (d x^{4} + c\right )}^{2} b - 2 \,{\left (d x^{4} + c\right )} b c + b c^{2} +{\left (d x^{4} + c\right )} a d - a c d\right )}} - \frac{{\left (4 \, b c + a d\right )} \arctan \left (\frac{\sqrt{d x^{4} + c}}{\sqrt{-c}}\right )}{a^{3} \sqrt{-c} c d^{3}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^4 + a)^2*sqrt(d*x^4 + c)*x^5),x, algorithm="giac")
[Out]